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PCB hatched ground plane resistance

# PCB hatched ground plane electrical resistance

**Problem Type:** plane-parallel problem of DC conduction.

**Geometry:**

Plane consists of the copper hexagonal cells with dimensions shown in the picture below. Plane thickness is 35 micrometers.

**Given:**

Electric conductivity of copper γ = 56e6 S/m;

**Task:**

DC current is flowing across the rectangular plane 180 mm x 100 mm between the electrodes welded to the diagonal corners. Calculate the electric resistance.

**Solution:**

Solution is based on the analysis of the currents flowing in the solid plane with equivalent electric conductivity. Task is performed in two steps.

- First we analyze the DC currents in the small square fragment of the hatched plane 4.8 mm by 4.8 mm. At the top side the square the positive potential of 1 mV is applied, bottom side is grounded (0 V). The current value is then calculated, which gives us the hatched plane fragment resistance.

*R_ = ΔU / I*

While the same size copper square resistance may be calculated analytically as

*R* = (1/γ) * *Length / Cross-section area*

Comparison of the calculated hatched plane fragment resistance and solid copper fragment resistance gives us the equivalent value of the hatched plane material *conductivity*.
- Then other QuickField problem is prepared where the current is flowing in the solid plane with equivalent conductivity and the resistance is found as ratio of the potential difference and current coming into the electrode.

**Results:**

*Step 1* problem:

Solid plate resistance: *R* = (1/56e6) * 4.8e-3 / (4.8e-3 * 35e-6) = 0.51 mOhm.

Hatched plane resistance: *R_* = 0.001 / 0.31 = 3.2 mOhm

Equivalent conductivity of the hatched plane material

γ_ = γ * (*R*/*R_*) = 56e6 S/m * (0.51 mOhm / 3.2 mOhm) = 8.9e6 S/m.

*Step 2* problem.

Resistance = Voltage drop / Current = 0.054 V / 1 A = 54 mOhm

Download simulation files (files may be viewed using any QuickField Edition).

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