Axisymmetric problem of electrostatics.
R = 100 mm, r=50 mm.
Relative permittivity of vacuum ε = 1,
The charge q = 10-9 C
Find the capacitance of spherical capacitor and compare it with analytical solution:
C = 4π·ε·ε0 · r·R / (R - r), [F]. *
Capacitor plate's surface is marked as 'floating conductor', i.e. isolated conductors with unknown potential. At some point on spheres' surface the charge is applied. The charge is then redistributed along the conductor surface automatically.
Potential distribution inside of the spherical capacitor.
The capacitance can be calculated as C = q / (U2-U1).
The measured potential difference is U2-U1 = 89.87 V.
The capacitance is C = 10-9/ 89.87 = 11.13·10-12 F
Watch online on YouTube.