ACElec1: Plane capacitor
This is an example of the plane capacitor simulation, performed with QuickField software. 
Problem Type: 
Plane problem of AC conduction. 
Geometry: 

Given: 
Relative permittivity of substrate ε = 10. 
Conductivity of substrate g = 10-10 S/m; 
Voltage U = 5 V, 
Frequency f = 1000 kHz. 
Loss tangent tan(δ) = 0.01
. 
Task: Calculate losses in capacitor

Solution: 
Capacitor with non-ideal dielectric can be replaced by electric circuit with ideal capacitor C and resistivity R connected in parallel. 
Active current due to dielectric conductivity g is very low. It could be calculated if we run the analysis with actual value of electric conductivity g. 

Results: 
Electric current vectors and electric potential distribution in plane capacitor 

Loss tangent tan(δ) = |PA / PR| = 0.0000695 / 0.00695 = 0.01. 	
Title

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Geometry model picture

Material data

Problem task

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Results: data + picture (full screen)