PCB thermal analysis

Problem Type:
3D problem of heat transfer.

Geometry:

pcb scheme

Given:

Item Loss [W] Volume [cm3]
CPU 2.5 4.62
IC 0.5 1.1
LM317 0.5 0.28
470 uF 0.2 2.26
1500 uF 0.15 0.8
Transformer 0.4 2.74
Diode 0.1 0.064
L1 0.1 2.08

FR4 board thermal conductivity λ = 0.25 W/K·m;
Radiator board thermal conductivity λ = 200 W/K·m;
Elements thermal conductivity λ = 1 W/K·m;
Convection coefficient α = 12 W/K·m2;

Problem:
Calculate the temperature distribution in a printed circuit board.

Solution:
QuickField takes losses values in [W/m3], so the ratio of loss [W] to volume [m3] from the table above is specified (for example, for CPU it is 2.5/4.62e-6).

Results:

pcb temperature distribution

See the pcb_temperature.pbm problem in the Examples folder.