Given: Copper electric conductivity σ = 56e6 S/m.
Current I = 100 A.
Problem: Determine the resistance of the bent copper wire.
Solution: The resistance R is equal to the ratio of voltage drop V to the current I R = V / I [Ohm]
We apply normal current density jn = I / A (where A is a wire cross-section area) at current terminal and zero potential at ground terminal. DC conduction simulation yields the current terminal electric potential V.
Result: Electric potential and current distribution in a wire:
Current terminal electric potential V = 0.00168 [V].
Resistance R = 0.00168 / 100 = 16.8 [uOhm].