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Two intersecting conducting planes electric field
Two conducting planes intersect at an angle β = 270°. The planes are assumed to be held at potential V. Find the electric field distribution near the corner.
Problem Type:
A plane problem of electrostatics.
Geometry:
Given:
Relative permittivity of vacuum ε = 1;
Volgate V = 100 V.
Solution:
Open space problem is converted to the closed region problem using the "zero potential" boundary far away from the studying object.
Comparison of results
Electric field strength distribution along the plane is shown in the table. The theoreticsl result is: E ~ r -1/3.
r, m |
QuickField |
Theory
(trend 6.3*r -1/3) |
0.1 |
13.46 V/m |
13.57 V/m |
0.2 |
10.69 V/m |
10.77 V/m |
0.5 |
7.89 V/m |
7.94 V/m |
1 |
6.3 V/m |
6.3 V/m |
1.5 |
5.52 V/m |
5.50 V/m |
2 |
5.03 V/m |
5.00 V/m |
3 |
4.43 V/m |
4.37 V/m |
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Reference
J.D.Jackson, Classical Electrodynamics, 3rd edition, Sect. 2.11.
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