A new approach to field modelling

de dk es fr it cz ru cn

RSS Twitter Facebook Linkedin YouTube

>> >> >>

Pair of parallel wires capacitance

Problem Type:
Plane problem of electrostatics.


pair of parallel wires

a1 = 4.72 mm, a2 = 1.13 mm, d = 100 mm.

Relative permittivity of vacuum ε = 1,
The charge q = 10-9 C
Model depth l = 1 m.

Find the mutual capacitance between two parallel wires and compare its value with analytical solution:
C = 2π·ε·ε0 l / ln( d2/a1·a2 ) [F]. *

Wire's surfaces are marked as 'floating conductor', i.e. isolated conductors with unknown potential. At some point on each of wire's surface the charge is applied. The charge is then redistributed along the conductor surface automatically.


Potential distribution.

pair of parallel wires capacitance

The capacitance can be calculated as C = q / (U2-U1). The measured potential difference is U2-U1 = 135 V.
The capacitance is C = 10-9 / 135 = 7.41·10-12 F



Theoretical result

C, pF
(model depth l = 1 m)



View movie Download video.

Watch online on YouTube.

Download PDF icon View simulation report in PDF.

Download Download simulation files.

*Power System Engineering, D.P.Kothari, I.J.Nargath.