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# Signal cable

Power and signal cable are buried in a common duct. Calculate the electric field distribution and find the mutual capacitance.

Problem Type:
Plane problem of Electrostatics.

Geometry:

Given:
The power cable consists of 4 isolated conductors (A, B, C, 0).
Voltage U = 660 V,
frequency f = 50 Hz.
The signal cable consists of 4 isolated conductors (s1, s2, s3, s4).

Problem:
Determine the mutual capacitance.

Solution:
To calculate self and mutual capacitances of conductors the Capacitance calculator addin is used.

Result:
Electric field strength at phase 60°:

 A B C 0 s2 s1 s4 s3 A 2.06e-011 5.76e-011 2.77e-012 5.63e-11 2.31e-014 2.15e-014 7.43e-015 8.01e-015 B 5.76e-011 2.06e-011 5.80e-011 2.75e-12 9.32e-013 1.27e-012 5.25e-013 3.24e-013 C 2.77e-012 5.80e-011 2.06e-011 5.75e-11 5.25e-013 1.24e-012 9.32e-013 3.24e-013 0 5.63e-011 2.75e-012 5.75e-011 2.06e-11 7.44e-015 2.1473e-014 2.3091e-014 8.0139e-015 s2 2.3127e-014 9.3256e-013 5.2505e-013 7.4404e-15 4.3477e-012 1.1255e-011 2.8165e-012 1.1127e-011 s1 2.1491e-014 1.2369e-012 1.2363e-012 2.1473e-14 1.1255e-011 3.1118e-012 1.1245e-011 2.831e-012 s4 7.4345e-015 5.252e-013 9.3176e-013 2.3091e-14 2.8165e-012 1.1245e-011 4.3443e-012 1.1119e-011 s3 8.0111e-015 3.2422e-013 3.2407e-013 8.0139e-15 1.1127e-011 2.831e-012 1.1119e-011 5.4758e-012