QuickField
A new approach to field modelling
Language:

order

evaluation

editions

version history

packages

components

programming

consulting

industrial

educational

scientific

sample problems

success stories

customers

webinars

virtual classroom

online courses

customer login

glossary

help

faq

 quickfield student edition user manual data libraries video free tools
 product news events blog publications subscription website changes
 tera analysis info resellers contact us about us

 Examples gallery Step-by-step tutorials Verification examples Programming examples Distributive examples

>> >>

# Thin film resistance

Electric current is passing through the steel thin film with two electrodes attached.

Problem type:
Plane problem of DC conduction.

Given:
h = 6 mm, g = 20 mm, d = 1 mm - thickness of the film
Electrical conductivity of the steel: γ = 10·106 Sm/m,
Voltage drop ΔU = 0.02 V.

Task:
Calculate the resistance of the steel film and compare with the analytical result.

Solution:
Current through the surface (I) is calculated in QuickField and then the resistance may be found using the Ohm's law:
R = ΔU / I

Analytical solution*:
R = (g/h + 0.469) / (γ·d).

Result:
QuickField: R = 0.02/52.6 = 3.80·10-4 Ohm.
Analytical solution: R = (0.020/0.006+0.469) / (10·106 · 0.001) = 3.80·10-4 Ohm.

Download simulation files (files may be viewed using any QuickField Edition).

*Conformal Mapping: Methods and Applications, Roland Schinzinger, Patricio A. A. Laura, 1991, Elsevier Science Publishers, B.V., p. 224. ISBN 0-486-43236-X (pbk).