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PCB heating
The voltage is applied to the sides of conducting sheet placed vertically and surrounded by the still air. The flowing current heats the sheet due to resistive losses. The front and back surfaces of the sheet are cooled by the air (natural convection).
Problem Type:
Plane problem of electrothermal coupling.
Geometry:
Given:
Data for magnetic analysis:
Sheet thickness d = 0.035 mm;
Material resistance ρ = 2·10^{8} Ohm/m;
Current I = 10 A;
Material heat conductivity λ = 380 W/K·m;
Convection coefficient α = 10 W/K·m^{2};
Problem:
Calculate the temperature and potential distribution in a conducting sheet.
Solution:
The resistive losses are calculated in the DC conduction problem. Then these losses are transferred to the linked heat transfer problem.
The sheet is cooled by convection from the front and back surface (total) F(T) = α·(T  T_{0})·(A_{front} + A_{back}), where α is a convection coefficient, and T_{0} is an ambient temperature, A_{front}, A_{back}  area of front and back surfaces, respectively.
The convection from other surfaces is ignored. We put T_{0} = 0 K and calculate overheating. The convection is modelled by the volume heat sink Q(T) = k·T, where coefficient k = 2α/d.
Results:
Potential distribution and current paths in the pcb 
Temperature distribution in the pcb (overheating) 


The pcb_current.pbm is the problem of calculating the current distribution, and pcb_heat.pbm analyzes temperature field.
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