Given: Relative magnetic permeability of steel μ = 100,
Conductivity of steel σ = 1'000'000 S/m,
External field B = 2.0 T, frequency f = 50 Hz... 100 kHz.
Determine the shielding factor at different frequencies.
Solution: LabelMover parametric tool is used to automate frequency sweep. LabelMover generates a set of QuickField problems (multiplying frequency by 2 at each step), simulates problems, calculates the magnetic flux density in the point of interest and place the results in the table.
Results Magnetic field strength distribtion at 50 Hz.