Plane capacitor dielectric loss - QuickField simulation example
This is an example of the plane capacitor simulation, performed with QuickField software.
How to calculate dielectric loss in a plane capacitor?
Answer Typical applications Geometry
Given
Task
Solution
Results
Engineering question
Convert loss tangent, frequency, and permittivity into effective dielectric conductivity in a plane-parallel AC conduction model.
multilayer HV insulation systems, cable insulation structures, bushing insulation assemblies
Download
Simulation problem
Problem Type
Plane-parallel problem of AC conduction.
Relative permittivity of dielectric ε = 10.
Voltage U = 5 V, frequency f = 1000 kHz.
Loss tangent tan(δ) = 0.01.
Calculate dielectric loss in the plane capacitor.
Dielectric loss and active power dissipation in a plane capacitor at 1 MHz for a dielectric with specified permittivity, conductivity, and loss tangent.:
g = 2πf·εε0·tan(δ) = 2·3.142·1000000·10·(8.854·10-12)·0.01 = 5.56·10-6 S/m.
Active power loss is PA = 0.0695 mW per 10 mm³.
Electric current vectors and electric potential distribution in plane capacitor
Video
Related examples