Cylindrical capacitor dissipation factor - QuickField simulation example
This is an example of the cylindrical capacitor simulation, performed with QuickField software. Capacitor consists of ceramic tube with silver electrodes mounted at the surface.
How to calculate capacitance and dissipation factor for a cylindrical ceramic capacitor?
Answer Typical applications Geometry
Given
Task
Solution
Results
Field distribution in cylindrical capacitor:
Engineering question
Calculate capacitance from charge over voltage and dissipation factor from the active-to-reactive power ratio.
layered dielectric structures, ceramic capacitor insulation systems, multilayer insulation components
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Simulation problem
Problem Type
Axisymmetric problem of AC conduction.
Relative permittivity of ceramic ε = 6.
Conductivity of ceramic g = 10 nS/m;
Voltage U = 10 V.
Frequency f = 1 kHz.
Determine capacitance and dissipation factor of the capacitor.
The value of dissipation factor can be calculated as tg(δ) = PA/PR. Capacitance can be calculated as C = q/U, where U is potential difference between electrodes and q - is a charge on electrodes.
Charge q = 27.7 pC.
Capacitance C = 2.77 pF.
Active power PA = 24.5 nW.
Reactive power PR = 817 nW.
Dissipation factor tg(δ) = 0.03.
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