A new approach to field modelling

Language:
Language Global English Deutsch Espanol Francais Italiano Danmark Ceske Chinese no-Pyccku


RSS Twitter Facebook Linkedin YouTube

>> >> >>

ACElec2: Cylindrical capacitor

This is an example of the cylindrical capacitor simulation, performed with QuickField software.

Problem Type:
Axisymmetric problem of AC conduction.

Geometry:

Cylindrical capacitor

Capacitor consists of ceramic tube with silver electrodes mounted at the surface.

Given:

Relative permittivity of air ε = 1.

Relative permittivity of ceramic ε = 6.
Conductivity of ceramic g = 10-8 S/m;
Voltage U = 10 V.
Frequency f = 1000 Hz.

Problem:

Determine capacitance and dissipation factor of the capacitor.

Solution:

The value of dissipation factor can be calculated as

The value of dissipation factor can be calculated as tg(δ) = PA/PR. Capacitance can be calculated as C = q/U, where U is potential difference between electrodes and q - is a charge on electrodes.

Results:
Field distribution in cylindrical capacitor:

Field distribution in cylindrical capacitor

QuickField

q, C

2.77·10-11

C, F

2.77·10-12

PA, W

2.45·10-8

PR, W

8.17·10-7

tg(δ)

0.03

View movie Download video

Watch online on YouTube.

Download PDF icon View simulation report in PDF.

Download icon Download simulation files (files may be viewed using any QuickField Edition).

There are no restrictions applied to the QuickField Student Edition postprocessors.
You can view field maps, make plots, calculate integrals and print pictures in the same way that the Professional Edition users do.