Dielectric losses - QuickField simulation example
Simulation of the dielectric losses in the capacitor with known loss tangent.
How to find dielectric losses in capacitors?
Answer Typical applications Geometry
Given
Task
Solution
Results
Active power dissipated in dielectric is PActive = 0.46 mW per 100mm³.
Reference:
Engineering question
Set up a plane-parallel QuickField AC Conduction problem for a capacitor structure and evaluate dielectric losses from computed field results.
capacitor dielectric materials, high-frequency capacitors, insulation dielectric systems
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Simulation problem
Problem Type
Plane-parallel problem of AC conduction.
d=1 mm, h=10 mm.
The length of capacitor in z direction is L = 10 mm.
Relative permittivity of substrate ε = 2.3, loss tangent tan(δ) = 0.0075.
AC voltage U = 220 V (r.m.s.), frequency f = 100 kHz.
Calculate dielectric losses in capacitor.
Electrical conductivity of materials should be set in AC conduction problems. We can take into account dielectric losses by specifying the apparent value of conductivity*:
σ = 2πf·εε0·tan(δ).
Apparent electric conductivity is σ = 2·3.142·100000·8.854e-12·2.3·0.0075 = 0.096 uS/m.
* Wikipedia, Dielectric loss.
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