Lead-acid battery internal resistance - QuickField simulation example
Internal resistance of a lead-acid battery cell formed by lead-grid plates immersed in sulfuric-acid electrolyte, including current flow in the electrolyte.
How to find lead acid battery internal resistance?
Answer Typical applications Geometry
Given
Task
Solution
Results
Current density and electric potential distribution in the grid electrode
Engineering question
Apply a known potential difference across the cell, calculate total current in the 3D DC-conduction model, and obtain internal resistance as Voltage drop / Current.
lead-acid battery cells, battery grid electrodes, electrochemical storage cells
Download
Simulation problem
Problem Type
3D problem of DC conduction.
Electric conductivity of lead 4.8 MS/m;
Electric conductivity of electrolyte 30 S/m;
Calculate the resistance of the cell.
To calculate the resistance we can apply a potential difference ΔV and measure the electric current value I. The resistance of a cell is then R = ΔV / I
We choose V+ = 1 V and V- = -1 V. So the potential difference is
ΔV = (V+) - (V-) = 2 V.
The model features symmetry, so only a positive grid-electrode is shown. On the plane of symmetry the U = 0V boundary condition is set.
Electric current value is 155 A. Resistance of the cell is R = 2/155 = 12.9 mOhm.
Related examples