Given: Relative permittivity of the insulator (glass) εr = 5,
Transmission line potential V = 10 kV (RMS, line to line voltage).
Ground voltage = 0 V.
Task: Calculate the electric field stress distribution on insulators surface.
Solution: Line voltage is measured between the phase conductors. The phase voltage (between phase conductor and ground) is √3 times smaller than the line voltage.
We should specify the peak voltage value (*√2).
Results: Electric field stress distribution along the suspension insulators' surface.
Video: Suspension insulator 00:00 Introduction
00:50 Transfer CAD model to QuickField through STEP file export/import.
02:40 Adding background region to the model. Selecting objects
03:40 Body labels' assigning. Hide/made transparent the body.
06:10 Selecting with rubber band.
07:05 Edit body labels physical properties
08:05 Boundary conditions on faces.
10:55 Model meshing and problem solving
11:25 Result analysis. Colored surface. Cut by plane.
12:55 Result analysis. 2D Section window local values, integrals. XY-plot along the custom contour. Local values, integrals.
15:40 Result analysis. Local values, integrals.
16:05 Result analysis. Change presentation types: slice plot, vectors, scatter plot. XY-plots.