QuickField

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Chip radiator heat sink

QuickField simulation example

Problem Type
3D problem of heat transfer.

Geometry
All length units are in millimeters.
Chip radiator heat sink Calculate radiator thermal resistance. Radiator 20 20 43 40 10 30 4 1 2 6 1

Given
Thermal conductivity of metal λ = 270 W/K-m.
Convection coefficient α = 15 W/(K·m²).
Ambient air temperature T0 = 20 °C.
Chip heat flux Q = 10 W.

Task
Calculate radiator thermal resistance.

Solution
Thermal resistance is the ratio of Temperature difference to Heat flux. As the heat flux is an input parameter, QuickField task is to calculate the temperature distribution.
QuickField takes an input heat flux as watts per meter square [W/m²]. So we should divide Q [W] by the chip surface area (which is 20mm x 20mm = 0.0004 m²).

Results
Temperature distribution in the heat sink:
Chip radiator heat sink temperature