QuickField

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Main >> Applications >> Sample problems

DIP socket capacitance

pin to pin capacitance

Problem Type: electrostatics.

Geometry: 3D Import
All dimensions are in millimeters

DIP socket 16 pins

Given:
Relative permittivity of dielectric ε = 3;
Relative permittivity of air ε = 1.

Task:
Calculate the capacitance between two adjacent pins #1 and #2.

Solution:
To calculate the capacitance we assign electric potentials +0.5 V to the pin #1 and -0.5 V to the pin #2. QuickField calculates electric field energy W in the entire space.
Capacitance is then calculated as:
C = 2*W / (V+ - V-)²

Results:
Electric field energy W = 1.4e-13 J.
Pin #1 to pin #2 capacitance
C = 2*1.43e-13 / 1² = 2.8e-13 F (0.28 pF).

Electric field stress distribution between two energized pins:

Electric field stress distribution between two energized pins

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