DIP socket capacitance

QuickField simulation example

Problem Type electrostatics.

Geometry 3D Import
All dimensions are in millimeters

Given
Relative permittivity of dielectric ε = 3;

Task
Calculate the capacitance between two adjacent pins #1 and #2.

Solution
To calculate the capacitance we assign electric potentials +0.5 V to the pin #1 and -0.5 V to the pin #2. QuickField calculates electric field energy W in the entire space.
Capacitance is then calculated as:
C = 2*W / (V⁺ - V^-)²

Results
Electric field energy W = 1.4e-13 J.
Pin #1 to pin #2 capacitance
C = 2*1.43e-13 / 1² = 2.8e-13 F (0.28 pF).

Electric field stress distribution between two energized pins:

• Video: DIP socket capacitance. Watch on YouTube
  
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