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QuickField simulation example
Problem Type Axisymmetric problem of electrostatics.
Geometry Insulator Grading ring HV Grounded Given Relative permittivity of insulator ε = 2; High voltage = 110 kV. Task Find the position of the grading ring, providing a linear distribution of potential along the insulator central axis. Solution In QuickField you must specify the amplitude of the phase voltage, which can be recalculated from the line voltage, as 110000 * √2 / √3. Problems with various ring position were automatically generated and calculated using the LabelMover utility. The calculation of the root-mean-square deviation from the linear dependence is performed in Microsoft Excel. Results Space distribution of the electric field strength and the electric potential distribution along the insulator central axis. *Reference: Corona ring in Wikipedia. Video: Grading ring. Watch on YouTube Download simulation files (files may be viewed using any QuickField Edition).
Given Relative permittivity of insulator ε = 2; High voltage = 110 kV.
Task Find the position of the grading ring, providing a linear distribution of potential along the insulator central axis.
Solution In QuickField you must specify the amplitude of the phase voltage, which can be recalculated from the line voltage, as 110000 * √2 / √3. Problems with various ring position were automatically generated and calculated using the LabelMover utility. The calculation of the root-mean-square deviation from the linear dependence is performed in Microsoft Excel.
Results Space distribution of the electric field strength and the electric potential distribution along the insulator central axis.
*Reference: Corona ring in Wikipedia.