Induction motor analysis - QuickField simulation example
This is a simulation example from Compumag TEAM Workshop Problem 30*.
How to find TEAM induction motor benchmark problem?
Answer Typical applications Geometry
Given
Task
Solution
It is not possible to specify the negative frequency in the problem. Instead we specify |fslip|, but consider the calculated torque value to be negative.
Results
Reference
Engineering question
Set up a plane-parallel QuickField AC Magnetics problem for an induction motor benchmark model and evaluate performance characteristics from computed field results.
TEAM benchmark induction motors, rotating field motors, induction motor test cases
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Simulation problem
Problem Type
Plane-parallel problem of AC magnetics.
Current density in a coil j = 310 A/cm² (r.m.s)
Frequency f = 60 Hz.
Aluminum conductivity 37.2 MS/m.
Relative permeability of steel μr=30.
Rotor steel conductivity 1.6 MS/m.
Stator steel is laminated and has a zero conductivity.
Calculate the torque, rotor steel and aluminum Joule heat losses and compare the results with a reference value.
To simulate the motion we will attenuate the AC problem frequency: fslip = slip * f,
where slip = 1 - (rotor angular frequency / synchronous angular frequency).
Synchronous angular frequency is 2πf = 2*3.142*60 = 377 rad/s.
Rotor
angular
frequency,
rad/s
Slip
Frequency fslip, Hz
0 1 60
200 0.469 28.2
400 -0.061 -3.66
600 -0.592 -35.5
800 -1.122 -67.3
1000 -1.653 -99.2
1200 -2.183 -131
Eddy current distribution at 28.2 Hz (equivalent to rotor angular frequency of 200 rad/s). Torque is 6 N*m, rotor steel losses are 15.7 W, rotor aluminum losses are 1061 W.
*Compumag TEAM Workshop
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