long solenoid inductance, magnetic FEA
Axisymmetric problem of DC magnetics.
R1 = 30 mm, R2 = 35 mm.
Current in the conductor i = 10 A;
Number of turns N = 100,
Length l = 0.5 m;
Calculate inductance of the long solenoid, side effects are neglected.
Inductance of the long solenoid can be obtained from the equation:
L = N ² · μ0 A / l,
where A is a cross-section area of the core (m²).
To calculate the inductance in QuickField you should divide magnetic flux by the source current.
L = N · Φ / i
Cross-section area of the core
A = π * ( (R1 + R2)/2 )² = 3.142 * ( (0.03+0.035)/2 )² = 0.00332 m².
Inductance of the long solenoid
L = 100² · 4e-7 · 3.142 * 0.00332 / 0.5 = 83.45 μH.
|Inductance L, μH||83.55||83.45||0.12%|
* Reference: John Bird, Electrical circuit theory and technology, p.77. ISBN-13: 978 0 7506 8139 1.