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Long solenoid inductance

QuickField simulation example

Problem Type
Axisymmetric problem of DC magnetics.

Geometry
Long solenoid inductance Calculate inductance of the long solenoid, side effects are neglected. Winding R1 R2

R1 = 30 mm, R2 = 35 mm.

Given
Current in the conductor i = 10 A;
Number of turns N = 100,
Length L = 0.5 m;

Task
Calculate inductance of the long solenoid, side effects are neglected.

Solution
Inductance of the long solenoid can be obtained from the equation:
L = N ² · μ0 A / L,
where A is a cross-section area of the core (m²).

To calculate the inductance in QuickField you should divide magnetic flux by the source current.
L = N · Φ / i

Results
Cross-section area of the core
A = π * ( (R1 + R2)/2 )² = 3.142 * ( (0.03+0.035)/2 )² = 0.00332 m².

Inductance of the long solenoid
L = 100² · 4e-7 · 3.142 * 0.00332 / 0.5 = 83.45 μH.
Long solenoid magnetic field

  QuickField Theory Δ, %
Inductance L, μH 83.55 83.45 0.12%

* Reference: John Bird, Electrical circuit theory and technology, p.77. ISBN-13: 978 0 7506 8139 1.