One turn loop inductance
QuickField simulation example
Engineering question
How to find single turn loop inductance
Engineering answer
Set up an axisymmetric QuickField DC Magnetics problem for a single-turn loop and evaluate inductance from computed field results.
Typical applications
single-turn loop inductors, RF loop antennas, calibration loop conductors
- Download simulation files (files may be viewed using any QuickField Edition).
Problem Type
Axisymmetric problem of DC magnetics
Geometry
Given
Current I = 50 A,
Loop radius R = 40 mm,
Wire diameter 2r = 10 mm.
Task
Calculate one turn loop inductance.
Solution
One turn loop inductance can be calculated using equation:
L = μ0 R · ( ln(8R/R) - 1.75 )
Results
Deviation from the analytic equation as a function or (R/r)
| r, mm | R/r | L, uH | Δ, %
| QuickField
| Reference*
| 5
| 8
| 0.1213
| 0.1211
| 0.17%
| 10
| 4
| 0.0875
| 0.0862
| 1.51%
| 16
| 2.5
| 0.0605
| 0.0622
| 2.73%
| 20
| 2
| 0.0550
| 0.0514
| 7.00%
| | |
* Reference: Clayton R. Paul Inductance: Loop and Partial, p.130. ISBN-13: 978 0 4704 6188 4.
- Video: One turn loop inductance. Watch on YouTube
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- Download simulation files (files may be viewed using any QuickField Edition).