One turn loop inductance
QuickField simulation example
Problem Type
Axisymmetric problem of DC magnetics
Geometry
Given
Current I = 50 A,
Loop radius R = 40 mm,
Wire diameter 2r = 10 mm.
Task
Calculate one turn loop inductance.
Solution
One turn loop inductance can be calculated using equation:
L = μ0 R · ( ln(8R/R) - 1.75 )
Results
Deviation from the analytic equation as a function or (R/r)
| r, mm | R/r | L, uH | Δ, % | |
| QuickField | Reference* | |||
| 5 | 8 | 0.1213 | 0.1211 | 0.17% |
| 10 | 4 | 0.0875 | 0.0862 | 1.51% |
| 16 | 2.5 | 0.0605 | 0.0622 | 2.73% |
| 20 | 2 | 0.0550 | 0.0514 | 7.00% |
* Reference: Clayton R. Paul Inductance: Loop and Partial, p.130. ISBN-13: 978 0 4704 6188 4.
- Video: One turn loop inductance. Watch on YouTube
- View simulation report in PDF
- Download simulation files (files may be viewed using any QuickField Edition).