One turn loop inductance
QuickField simulation example
Problem Type
Axisymmetric problem of DC magnetics
Geometry
Given
Current I = 50 A,
Loop radius R = 40 mm,
Wire diameter 2r = 10 mm.
Task
Calculate one turn loop inductance.
Solution
One turn loop inductance can be calculated using equation:
L = μ0 R · ( ln(8R/R) - 1.75 )
Results
Deviation from the analytic equation as a function or (R/r)
r, mm | R/r | L, uH | Δ, % | |
QuickField | Reference* | |||
5 | 8 | 0.1213 | 0.1211 | 0.17% |
10 | 4 | 0.0875 | 0.0862 | 1.51% |
16 | 2.5 | 0.0605 | 0.0622 | 2.73% |
20 | 2 | 0.0550 | 0.0514 | 7.00% |
* Reference: Clayton R. Paul Inductance: Loop and Partial, p.130. ISBN-13: 978 0 4704 6188 4.
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