Planar heater 3D - QuickField simulation example
The planar heater is placed between two layers of glass of irregular shape. The heater consists of a serpentine stripe carrying electric current. QuickField is used to calculate the temperature distribution in the glass.
How to find temperature distribution in planar glass heater?
Answer Typical applications Geometry
Given
Task
Solution
Result
Average heat flux generated by the planar heater is (171.76 - 51.02) / 0.42977 = 281 W/m².
Engineering question
Set up a 3D QuickField Steady-state Heat Transfer problem for a planar glass heater and evaluate temperature distribution from computed field results.
planar glass heaters, transparent heating panels, surface film heaters
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Simulation problem
Problem Type
A 3D problem of Heat Transfer.
There are 10 mm paddings between the glass edges and the heater.
Heater power 600 W/m².
Indoor air temperature is +20°C, convection coefficient is 8 W/m²*K.
Outdoor air temperature is -15°C, convection coefficient is 23 W/m²*K.
Calculate temperature distribution in the glass.
Film thickness (~0.01 mm) is much less than the glass thickness. So we do not model film as a body, but as a surface with a surface power heat specified instead. For simplicity we assume that the heating power is evenly distributed in the serpentine stripe.
Glass inner surface average temperature is +5.3°C, outdoor surface average temperature is +2.4°C.
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