QuickField

A new approach to field modelling

Main >> Applications >> Sample problems >> Shallow foundation thermal resistance

# Calculation of the shallow foundation thermal resistance

QuickField simulation example

Using the shallow foundation to compare with the traditional deep foundation allows reduction of the expenses on building materials, work time and the cost of the project. But in the cold climate shallow foundations require additional thermal insulation. EPS plate placed directly under the foundation is one of these methods.

Problem Type

Geometry

Given
Temperature inside (upper edge of the foundation): T1 = +20 °C;
Temperature outside (ground surface): T2 = -20 °C;

Compare thermal resistance of the shallow foundation with the insulation plate and without the plate.

Solution
Thermal resistance can be calculated as a ratio of the temperature difference value and the heat flux value.

Results
Insulation plate reduces heat losses by 10%:

Design Temperature difference (°C) Heat flux (W) Thermal resistance(°C/W)
Insulated 40 72.97 0.55
Without insulation 40 81.15 0.49

Temperature distribution in the shallow foundation:

• Insulated
• Without insulation