Moving slab heating in the inductor - QuickField simulation example
Steel slab is moving through the inline induction heater with 6 m/min speed. Find the temperature distribution in the slab.
How to find temperature distribution in moving steel slab induction heater?
Answer Typical applications Geometry
Given
Task
Solution
The heating time is t = Inductor length / slab speed = 0.6/0.1 = 6 seconds. We specify time-dependent power sources in transient thermal problem: Q * impulse(t,0,6). The solution time is set to be 10 seconds, so that we can simulate the heating and the subsequent cooling in the same problem.
Results
We are grateful to Selit S.R.L. for providing us with the idea of this model.
Engineering question
Set up a plane-parallel QuickField Transient Heat Transfer problem for a moving steel slab induction heater and evaluate temperature distribution from computed field results.
moving slab induction heaters, strip processing induction lines, steel slab heaters
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Simulation problem
Problem Type
Plane-parallel problem of Transient heat transfer.
Inductor length is 0.6 m, slab speed is 6 m/min (0.1 m/s).
Power density in the slab layers was calculated in the related AC magnetic example: Q0 = 34.0 MW/m³, Q1 = 27.3 MW/m³, Q2 = 19.4 MW/m³ Q3 = 11.4 MW/m³ Q4 = 5.8 MW/m³ Q5 = 2.1 MW/m³ Q6 = 0.29 MW/m³.
Slab initial temperature is +900°C. Slab surface emissivity coefficient ε = 0.8, ambient temperature is +20°C.
Density of steel ρ = 7880 kg/m³.
Calculate the temperature distribution in the steel slab.
We analyze the temperature distribution in one slab cross-section which moves inside the inductor.
We neglect the heat redistribution along the slab and consider the heating of a cross-section due to the internal heat sources and cooling by the radiation from the surface only.
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