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Transmission line inductance matrix

QuickField simulation example

Transmission line consists of three phase conductors A, B, C placed above the earth. The single inductance value is not enough to describe this system. There are self inductance of each conductor and mutual inductance between conductors.
To understand the concept of mutual inductance you can think of some real case scenarios. For example, only phases A and B are energized and phase C is under maintenance and is grounded on both sides. The induced current in the C - ground loop depends on the mutual inductance between the C and other phase conductors.
In this example we calculate the transmission line inductance matrix.

Problem Type
Plane-parallel problem of DC magnetics.

Geometry
Transmission line inductance matrix Transmission line consists of three phase conductors A, B, C placed above the earth. The single inductance value is not enough to describe this system. There are self inductance of each conductor and mutual inductance between conductors. LA LB LC MAB MAC MBC C A B soil 2 m 3.5 m 2 m 3 m 14.5 m 19 wires by Ø3.447mm 177.3 mm² All Aluminum Stranded Conductor (ACC) Simplified AAC model

Given
ACC conductor* consists of 19 aluminum wires with a diameter of 3.447 mm each.

Task
Calculate the transmission line inductance matrix.

Solution
To measure inductance we energize one of the phase conductors and let the current return through the ground. Flux linkage with each conductor is measured. Then self- and mutual inductance values are calculated: Inductance = Flux linkage / Electric current.
Alternatively, we can measure energies. To measure the self inductance we energize one of the phase conductors and let the current return through the ground.
Inductance = 2 · Magnetic field energy / (Electric current)²

To calculate the mutual inductance we put forth and back current in two of three phase conductors. There is no current in the soil nor in the free phase conductor in this case.
This way the line-to-line loop inductance value is calculated. To convert it to the phase-to-phase mutual inductance the following equation** is used:
Lloop AB = LA + LB - 2·MA-B
This yelds MA-B = ½(LA + LB - Lloop AB)

Results
Calculations are done per 1 km of the transmission line length. Test electric current value is 100 A.

Inductance = Magnetic flux linkage / Electric current
Energized
phase
Measured flux linkage, Wb/km Inductance values, mH/km
A B C A B C
A 0.19684 0.07160 0.06374 1.968 0.716 0.637
B 0.19664 0.061887 1.966 0.618
C 0.19663 1.966

Inductance = 2 * Magnetic field energy / (Electric current)²
Energized
phases
Measured
energy,
J/km
Self
inductance
L, mH/km
Loop
inductance,
mH/km
Phase-to-phase
mutual inductance
M, mH/km
A 9.6185 1.923
B 9.5979 1.920
C 9.5979 1.920
A+,B- 12.316 2.463 ½·(1.923+1.920-2.463) =
= 0.690
A+,C- 13.091 2.618 ½·(1.923+1.920-2.618) =
= 0.612
B+,C- 13.275 2.655 ½·(1.920+1.920-2.655) =
= 0.592

Transmission line inductance matrix

References
* Daffodil, All Aluminum Stranded Conductor
** Clayton R. Paul Inductance: Loop and Partial, page 315 "Modeling a two-wire transmission line with partial inductances". ISBN-13: 978 0 4704 6188 4.