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Double wound solenoid
This is an example of the coil simulation, performed with QuickField software.
Problem Type:
Axisymmetric multiphysics problem of Transient magnetics coupled to Steady-state heat transfer.
Geometry:
Given:
Copper electric conductivity σ = 56 MS/m.
Voltage U = 0.1 V.
Ambient air temperature T0 = 20°C.
Convection coefficient average value α = 5 W/K-m².
Task:
DC voltage is applied to the coil. Calculate the inductance, resistance and steady-state temperature.
Solution:
Transient magnetic formulation in QuickField allows assigning electric conductivity to blocks and connect blocks using the external electric circuit. The coil resistance can be calculated using circuit-simulation results: R = V / I.
The coil inductance can be calculated using the field simulation results: L = 2*Energy / I ².
The coil temperature is calculated in heat transfer problem that is linked to transient magnetics problem.
Result:
Double wound solenoid current I = 2.0 A, resistance R = 0.1 / 2.0 = 0.05 Ohm.
Magnetic field energy W = 5.65 uJ, inductance L = 2*5.65 / 2.0 / 2.0 = 2.8 uH.
Solenoind winding temperature +47°C.
