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Double wound solenoid

coil transient current, double layered coil, dual wound coil

This is an example of the coil simulation, performed with QuickField software.

Problem Type
Axisymmetric multiphysics problem of Transient magnetics coupled to Steady-state heat transfer.

Geometry
Double wound solenoid DC voltage is applied to the coil. Calculate the inductance, resistance and steady-state temperature. 1 12 2 11 3 10 4 9 5 8 6 7 Winding Ø 20 mm

Given
Copper electric conductivity σ = 56 MS/m.
Voltage U = 0.1 V.
Ambient air temperature T0 = 20°C.
Convection coefficient average value α = 5 W/K-m².

Task
DC voltage is applied to the coil. Calculate the inductance, resistance and steady-state temperature.

Solution
Transient magnetic formulation in QuickField allows assigning electric conductivity to blocks and connect blocks using the external electric circuit. The coil resistance can be calculated using circuit-simulation results: R = V / I.
The coil inductance can be calculated using the field simulation results: L = 2*Energy / I ².
The coil temperature is calculated in heat transfer problem that is linked to transient magnetics problem.

Result:
Double wound solenoid current I = 2.0 A, resistance R = 0.1 / 2.0 = 0.05 Ohm.
Magnetic field energy W = 5.65 uJ, inductance L = 2*5.65 / 2.0 / 2.0 = 2.8 uH.
Solenoind winding temperature +47°C.
Double wound solenoid

  • Download simulation files (files may be viewed using any QuickField Edition).
  • New version QuickField 6.5

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