Main >> Applications >> Sample problems >> Double wound solenoid

# Double wound solenoid

coil transient current, double layered coil, dual wound coil

This is an example of the coil simulation, performed with QuickField software.

Problem Type
Axisymmetric multiphysics problem of Transient magnetics coupled to Steady-state heat transfer.

Geometry

Given
Copper electric conductivity σ = 56 MS/m.
Voltage U = 0.1 V.
Ambient air temperature T0 = 20°C.
Convection coefficient average value α = 5 W/K-m².

DC voltage is applied to the coil. Calculate the inductance, resistance and steady-state temperature.

Solution
Transient magnetic formulation in QuickField allows assigning electric conductivity to blocks and connect blocks using the external electric circuit. The coil resistance can be calculated using circuit-simulation results: R = V / I.
The coil inductance can be calculated using the field simulation results: L = 2*Energy / I ².
The coil temperature is calculated in heat transfer problem that is linked to transient magnetics problem.

Result
Double wound solenoid current I = 2.0 A, resistance R = 0.1 / 2.0 = 0.05 Ohm.
Magnetic field energy W = 5.65 uJ, inductance L = 2*5.65 / 2.0 / 2.0 = 2.8 uH.
Solenoind winding temperature +47°C.

• Download simulation files (files may be viewed using any QuickField Edition).

•  Product Order Evaluation request Editions Version history Packages Components Programming Consulting Applications Industrial Educational Scientific Sample problems Success stories Customers Support Webinars Virtual Classroom Online courses Customer login Glossary QuickField help FAQ
 Downloads QuickField Student Edition User manual Data Libraries Video Free tools News Product News Events Publications Subscription Contacts Tera Analysis info Resellers Contact us Online chat About us