Superconducting fault current limiter. Single coil with ferrite core - QuickField simulation example
This simulation example is prepared by Professor James R. Claycomb as a part of the webinar Fault Current Limiter Simulations using QuickField.
How to calculate fault current in a superconducting fault current limiter?
Answer Typical applications Geometry
Given
Task Solution
Results
Fault current in a superconducting limiter consisting of a single excitation coil with a ferrite core and a superconducting shielding element.
Engineering question
Solve the AC-magnetic limiter for superconducting, intermediate, and normal material states and compare the resulting circuit currents to obtain the fault current.
superconducting fault current limiters, inductive protection reactors, grid protection devices
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Simulation problem
Problem Type
Axisymmetric problem of AC magnetics.
Iron core permeability is 500.
Winding number of turns is 24, conductor cross-section area is 4 mm², copper conductivity is 57 MS/m.
Voltage source is 12 V, frequency 50 Hz.
Superconductor permeability is a non-linear function of magnetic field strength:
Calculate the fault current.
Three problems are simulated:
- superconductor in a superconducting state (μ=10-6);
- superconductor in an intermediate state (BH-curve is specified);
- superconductor in a normal state (μ=1).
The picture shows how the state of the superconductor changes from superconducting to intermediate to normal. The fault current value changes from 799A to 557A to 118A respectively.
Video
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