Superconducting fault current limiter - QuickField simulation example
This simulation example is prepared by Professor James R. Claycomb as a part of the webinar Fault Current Limiter Simulations using QuickField.
How to calculate fault current in a superconducting fault current limiter?
Answer Typical applications Geometry
Given
Task Solution
Results
Fault current in a superconducting current limiter as the superconducting element changes state under excessive magnetic-field and current conditions.
Engineering question
Compare the AC-magnetic circuit with the shield in superconducting and normal states to determine how the transition of the superconductor affects the fault current.
superconducting fault current limiters, inductive protection reactors, grid protection devices
Download
Simulation problem
Problem Type
Axisymmetric problem of AC magnetics.
Mu-metal permeability 10000
Primary winding number of turns is 93, secondary winding number of turns is 54.
Conductor diameter is 1 mm, copper conductivity 59.6 MS/m.
Voltage source 120 V, frequency 60 Hz.
Superconductor permeability in superconducting state is 0.00001, in normal state 1.
Calculate the fault current.
First a hypothetic case is simulated - the superconductor remains in the superconducting state, despite the high value of magnetic flux density. This case reveals the maximum possible value of a fault current.
In fact, the superconductor becomes normal in intense magnetic field and that is the second simulation case. The fault current magnitude is calculated in case the superconductor becomes normal.
A maximum possible fault current magnitude is 739 A. The fault current limiter reduces fault current magnitude to 477 A.
Left picture shows a hypothetic case simulation results, when the superconductor remains superconducting and fully screens off the secondary winding. Right picture shows a real case simulation result: the superconductor is in a normal state.
Video
Related examples