QuickField

A new approach to field modelling
Language:
Global English Deutch Espanol Francais Italiano Danmark Ceske Chinese Pycckuü

Main >> Applications >> Sample problems >> Copper inductor with a steel tube

Copper inductor with a steel tube

A 2-turns copper inductor is used to heat the cylindrical steel part.

Problem Type:
Axisymmetric multiphysics problem of AC magnetics coupled to Transient heat transfer.

Geometry:

solenoid model

Given:
Inductor current I = 1000 A;
Inductor frequency f = 22 kHz;
Relative permeability of air and copper μ = 1;
Relative permeability of steel μ = 400;
Electric conductivity of steel σ = 5000000 S/m;
Thermal conductivity of steel λ = 20 W/K*m;
Volume mass density of steel ρ = 7800 kg/m³;
Specific heat of steel C = 200 J/K*kg;

Task:
Calculate the temperature distribution in the steel part after 10 seconds of heating.

Solution:
Penetration depth in the steel part is less than 0.1 mm at this frequency. To get accurate results it is required to build very dense mesh on the surface of the steel part.

Results:
Current density distribution in the steel part
Induction heating simulation: Current density distribution

Temperature distribution in the steel part
Induction heating simulation: Temperature distribution

See the Inductor_magn.pbm and inductor_heat.pbm problems for the magnetic and thermal analysis respectively.

  • Video:

    Magnetic problem

    Coupled thermal problem


    See more videos in QuickField Analysis for Induction heating webinar.
  • View simulation report in PDF
  • Download simulation files (files may be viewed using any QuickField Edition).

    Transformers simulation with QuickField. Part 2